线段树模板

Posted by KalosAner on January 4, 2025

一、动态开点版

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
#include <iostream>

using namespace std;

class Node {
private:
    Node *left, *right;
    int val, add;
public:
    void update(Node* cur, int start, int end, int l, int r, int val) {
        if (l <= start && end <= r) {
            cur->val += (end - start + 1) * val;
            cur->add += val;
            return ;
        }
        int mid = (start + end) >> 1;
        pushDown(cur, mid - start + 1, end - mid);
        if (l <= mid) update(cur->left, start, mid, l, r, val);
        if (r > mid) update(cur->right, mid + 1, end, l, r, val);
        pushUp(cur);
    }
    int query(Node* cur, int start, int end, int l, int r) {
        if (l <= start && end <= r) return cur->val;
        int mid = (start + end) >> 1, ans = 0;
        pushDown(cur, mid - start + 1, end - mid);
        if (l <= mid) ans += query(cur->left, start, mid, l, r);
        if (r > mid) ans += query(cur->right, mid + 1, end, l, r);
        return ans;
    }
    void pushUp(Node* cur) {
        cur->val = cur->left->val + cur->right->val;
    }
    void pushDown(Node* cur, int leftNum, int rightNum) {
        if (cur->left == nullptr) cur->left = new Node();
        if (cur->right == nullptr) cur->right = new Node();
        if (cur->add == 0) return ;
        cur->left->val += cur->add * leftNum;
        cur->right->val += cur->add * rightNum;
        // 对区间进行「加减」的更新操作,下推懒惰标记时需要累加起来,不能直接覆盖
        cur->left->add += cur->add;
        cur->right->add += cur->add;
        cur->add = 0;
    }
};

int main() {
    Node* root = new Node();
    int N = 1e5;
    root->update(root, 0, N, 1, 115, 3);
    root->update(root, 0, N, 12, 55, 68);
    root->update(root, 0, N, 37, 90, 7);
    root->update(root, 0, N, 34, 60, 5);
    root->update(root, 0, N, 12, 33, 3);
    root->update(root, 0, N, 23, 56, 6);
    root->update(root, 0, N, 31, 134, 16);
    root->update(root, 0, N, 62, 156, 47);
    root->update(root, 0, N, 1, 24, 52);
    for (int i = 0; i <= 200; ++ i) {
        cout << root->query(root, 0, N, i, i) << ' ';
    }
    return 0;
}